bash递归函数测试
#!/bin/bash
# using recursion
function factorial {
if [ $1 -lt 1 ]
then
echo 0
elif [ $1 -eq 1 ]
then
echo 1
else
local temp1=$1
local temp2=$(factorial $[ $1 - 1 ])
local result=$[ $temp1 * $temp2 ]
echo $result
fi
}
function sumn {
if [ $1 -lt 1 ]
then
echo 0
elif [ $1 -eq 1 ]
then
echo 1
else
local temp1=$1
local temp2=$(sumn $[ $1 - 1 ])
local result=$[ $temp1 + $temp2 ]
echo $result
fi
}
function fbnq {
if [ $1 -lt 1 ]
then
echo 0
elif [ $1 -lt 2 ]
then
echo 1
else
local temp1=$(fbnq $[ $1 - 1 ])
local temp2=$(fbnq $[ $1 - 2 ])
local result=$[ $temp1 + $temp2 ]
echo $result
fi
}
read -p "Enter value: " value
result=$(factorial $value)
totalsum=$(sumn $value)
fibon=$(fbnq $value)
echo "The factorial of $value is: $result"
echo "The total sum of $value is: $totalsum"
echo "FibonacciRecursive of $value is: $fibon"
递归实现只有2步:构造递归表达式以及设定初值。